Anonymous asked in Science & MathematicsChemistry · 1 month ago

Calculate mass of Copper(II) acetate monohydrate.... (from solution-detail inside)?

Basically title. 

Calculate mass of Copper(II) acetate monohydrate needed to prepare 100.0 mL of 0.1250 M solution from solid Copper(II) acetate monohydrateI really confused on how to start it. I really tried but am beyond stuck. I also like to learn on how exactly to do this problem-so what topic should i search on youtube? thx 

1 Answer

  • 1 month ago
    Favorite Answer

    Calculate the moles of Cu(II) acetate [Cu(C2H5O2)2*H2O] required:

    0.1250 mol/L X 0.1000 L = 0.01250 mol Cu(C2H5O2)2*H2O

    The molar mass of the compound is 199.65 g/mol (Are you OK with figuring that out?)

    Mass Cu(C2H5O2)2*H2O = 0.01250 mol X 199.65 g/mol = 2.496 g 

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