When the horses up-root the stump, what is the acceleration of the stump if it has a mass of 27.1kg?

Two horses are pulling on a tree stump. One horse pulls on the stump with a force of 7.2N to the east and the second horse pulls on the stump with a force of 6.3N to the south. When the horses up-root the stump, what is the acceleration of the stump if it has a mass of 27.1kg?

I got an answer of a= 0.35 m/s^2, 49 degrees E of S. Am I right?

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  • 1 month ago
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    Forces are perpendicular to each other. Find the resultant force using Pythagorean Theorem.

    Fres = sqrt(Fs^2 + Fe^2)

    Fres = sqrt(6.3^2 + 7.2^2) = 9.6 N

    The angle A between this force and South direction

    cos A = Fs / Fres

    A = arccos (Fs / Fres)

    A = arccos (6.3 / 9.6) = 49°

    Acceleration:

    a = Fres/m

    a = 9.6 / 27.1 = 0.35 m/s^2

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