# What is the mass in grams of solute in, 1. 250mL of 0.264 M H2 O2 2. 37.0mL of 5.75×10^-4 M benzoic axis ( 122g/mol) ?

3. 4.50L of a solution that contains 31.7 ppm of SnCI2

4. 11.7 mL of 0.0225 M KBrO3

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- jacob sLv 71 month agoFavorite Answer
1.) 0.264 mol H2O2/L x 1L/1000ml x 34.02g H2O2/mol x 250ml =2.25g H2O2

2.) 5.75×10^-4 benzoic acid/L x 1L/1000ml x 122g benzoic acid/1mol x 32 ml=

2.60 x 10^-3 g benzoic acid

3.) 31.7 mg SnCI2/L x 1g/1000mg x 4.50L = 0.143g SnCI2

4.) 0.0225 mol KBrO3/1L x 1L/1000ml x 167g KBrO3/mol x 11.7ml =

4.40 x 10^-2g KBrO3

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