Object travel distance?
Applying 3000 kinetic energy to a Mass(10kg) laying on a surface with friction of 0.1μ how long will the mass travels before fully stop.
Is my answer correct?
½mv² = μmgd
= 305.81 meters
It was 3000 mechanic energy, as the potential gravitational energy was 0, so only left the kinetic energy. And coefficient of dynamic friction = 0.1μ
- oubaasLv 74 weeks agoFavorite Answer
3000/10 = g*μd*d
d = 300/(9.806*0.1) = 306 m
- NCSLv 74 weeks ago
Your answer is correct for a value of g = 9.81 m/s²
- Demiurge42Lv 74 weeks ago
Kinetic energy isn't something that's applied. It's a property an object has based on it's mass and speed. "...friction of 0.1μ" also makes no sense.
- billrussell42Lv 74 weeks ago
3000 kinetic energy ?? what are the units ?
"friction of 0.1μ" ?? what does this mean ?
if I has to guess, those would be
KE = 3000 J
and coef. of friction, μ = 0.1