Sam asked in Science & MathematicsPhysics · 3 months ago

plz help for this physics problem?

a car is traveling at 60 km/hr a car tire is rotating at a rate of approximately 1500 revolutions per minute, determine

a) the frequency of the tire rotation in hertz

b) the period of the tire rotation

c) if you increased the velocity of the car what would happen to the value of the frequency and the period

3 Answers

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  • oubaas
    Lv 7
    3 months ago
    Favorite Answer

    a car is traveling at 60 km/hr a car tire is rotating at a rate of approximately 1500 revolutions per minute, determine

    a) the frequency of the tire rotation in hertz

    f = n/60 = 1500/60 = 150/6 = 25 Hz

    b) the period of the tire rotation

    period T = 1/f = 1/25 = 0,040 sec (40 msec) 

    c) if you increased the velocity of the car what would happen to the value of the frequency and the period

    f increases, T decreases 

  • 3 months ago

    60km/hr * 1000m/km * 1hr/3600s = 50/3 m/s = V = ωr = 2π*f*r

    1500rev/60s * 2πrad/rev = 50π rad/s = ω so f = 50π/2π = 25Hz <<<<< a)

    T = 0.04s = 40ms <<<<< b)

    50/3 = 50π * r so r = 0.106m

    Higher V is higher frequency f and shorter period T <<<<< c)

  • NCS
    Lv 7
    3 months ago

    1500 rev/min * 1min/60s * 2π rads/rev = 157 rad/s = ω

    a) f = ω / 2π = 25 Hz

    b) T = 1/f = 0.04s

    c) v↑ then ω↑ and so f↑ and T↓

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