# plz help for this physics problem?

a car is traveling at 60 km/hr a car tire is rotating at a rate of approximately 1500 revolutions per minute, determine

a) the frequency of the tire rotation in hertz

b) the period of the tire rotation

c) if you increased the velocity of the car what would happen to the value of the frequency and the period

### 3 Answers

- oubaasLv 73 months agoFavorite Answer
a car is traveling at 60 km/hr a car tire is rotating at a rate of approximately 1500 revolutions per minute, determine

a) the frequency of the tire rotation in hertz

f = n/60 = 1500/60 = 150/6 = 25 Hz

b) the period of the tire rotation

period T = 1/f = 1/25 = 0,040 sec (40 msec)

c) if you increased the velocity of the car what would happen to the value of the frequency and the period

f increases, T decreases

- oldschoolLv 73 months ago
60km/hr * 1000m/km * 1hr/3600s = 50/3 m/s = V = ωr = 2π*f*r

1500rev/60s * 2πrad/rev = 50π rad/s = ω so f = 50π/2π = 25Hz <<<<< a)

T = 0.04s = 40ms <<<<< b)

50/3 = 50π * r so r = 0.106m

Higher V is higher frequency f and shorter period T <<<<< c)

- NCSLv 73 months ago
1500 rev/min * 1min/60s * 2π rads/rev = 157 rad/s = ω

a) f = ω / 2π = 25 Hz

b) T = 1/f = 0.04s

c) v↑ then ω↑ and so f↑ and T↓