# Physics Grade 10 Need urgent help  ?

I'm currently studying reflection on a concave mirror and this is the question i'm stuck on

1. A 6.0 cm tall object is placed 8.0 cm away from a concave mirror

a) how far away is the inverted image if it's height is 4.5 cm (hint: inverted, see rules for h)

b)what is the magnification of this mirror

c) is the image real or virtual ? justify your answer with 2 valid points.

idk whether to solve this with drawing it or using the equations

idk when to use the magnification equation and the other one

PLZ HELP ASAP!!!!!

Relevance

a) By m = hi/ho = -di/do

=>di = dohi/ho {-ve is just indicating the image is real}

=>di = [8 x 4.5]/6

=>di = 6 cm

b)  By m = hi/ho = 4.5/6 = 0.75

c) For concave mirror, this condition only exists when the Object is beyond centre of curvature and in such situation, the characteristics of the image are as under;

-Real image

-Inverted (vertically)

-Reduced (diminished/smaller)

-As the distance of the object (S) increases, the image asymptotically approaches the focal point

-In the limit where S approaches infinity, the image size approaches zero as the image approaches F

=>Real image