Ramez asked in Science & MathematicsPhysics · 2 months ago

A ball is thrown vertically from ground level and it rises to a maximum height of 50 m. Calculate the time at which 50 m is reached.?

3 Answers

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  • ?
    Lv 7
    2 months ago

    v = u + at

    so, 0 = u - gt

    i.e. u = gt

    Also, v² = u² + 2as

    so, 0 = u² - 2g(50)

    Then, u² = 100g

    Hence, (gt)² = 100g

    => g²t² = 100g

    i.e. t² = 100/g

    Hence, t = 10/√g => 3.19 seconds

    :)>

  • 2 months ago

    Max height is defined as the moment when Vy = 0

    Vy(t) = Vyo - g*t = 0 at t = Vyo/g but 50 = Vyo²/19.6 so Vyo² = 19.6*50 = 31.3²

    t = 31.3/9.8 = 3.2s <<<<<

  • 2 months ago

    time to fall 50 m = t = √(2h/g) = √(2•50/9.8) = 3.19 s

    falling object starting from rest (and reverse)h is height in meters, t is time falling in seconds,g is acceleration of gravity, usually 9.8 m/s²v is velocity in m/sh = ½gt²t = √(2h/g)v = √(2gh)h = v²/2gv = gt

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