Write the standard from through the point given with the given slope ?

Through: ( 1,2 )     slope =7

6 Answers

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  • 2 months ago

    y-2=7(x-1)

    =>

    7x-y-5=0 (answer)

  • 2 months ago

    y = 7x - 5

  • 2 months ago

    The typical equation of a line is: y = mx + y₀ → where m: slope and where y₀: y-intercept

    The slope is (7), so the equation of the line becomes: y = 7x + y₀

    The line passes through (1 ; 2), so the coordinates of this point must verify the equation of the line.

    y = 7x + y₀

    y₀ = y - 7x → you substitute x and y by the coordinates of the point (1 ; 2)

    y₀ = 2 - (7 * 1)

    y₀ = - 5

    The equation of the line is: y = 7x - 5

  • Pope
    Lv 7
    2 months ago

    This is one of a hundred ways. I would begin with point-slop form, expand, and group terms with the x and y terms left and the constant on the right.

    y - 2 = 7(x - 1)

    y - 2 = 7x - 7

    -7x + y = -5

    7x - y = 5

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  • 2 months ago

    Standard form of a linear equation is:

    Ax + By = C

    Where A, B, and C are integers and A is positive.

    Starting with the slope-intercept form of a line and substitute what we know to solve for the unknown intercept:

    y = mx + b

    2 = 7(1) + b

    2 = 7 + b

    -5 = b

    So the slope-intercept form is:

    y = 7x - 5

    To put this into standard form, move the "x" term to the left side then multiply both sides by -1 since the leading coefficient is negative:

    -7x + y = -5

    7x - y = 5

  • Ian H
    Lv 7
    2 months ago

    y = mx + c

    y = 7x - 5

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