Write the standard from through the point given with the given slope ?

Question

Through: ( 1,2 )     slope =7

Answer 1

y-2=7(x-1)

=>

7x-y-5=0 (answer)

Answer 2

y = 7x - 5

Answer 3

The typical equation of a line is: y = mx + y₀ → where m: slope and where y₀: y-intercept

The slope is (7), so the equation of the line becomes: y = 7x + y₀

The line passes through (1 ; 2), so the coordinates of this point must verify the equation of the line.

y = 7x + y₀

y₀ = y - 7x → you substitute x and y by the coordinates of the point (1 ; 2)

y₀ = 2 - (7 * 1)

y₀ = - 5

The equation of the line is: y = 7x - 5

Answer 4

This is one of a hundred ways. I would begin with point-slop form, expand, and group terms with the x and y terms left and the constant on the right.

y - 2 = 7(x - 1)

y - 2 = 7x - 7

-7x + y = -5

7x - y = 5

Answer 5

Standard form of a linear equation is:

Ax + By = C

Where A, B, and C are integers and A is positive.

Starting with the slope-intercept form of a line and substitute what we know to solve for the unknown intercept:

y = mx + b

2 = 7(1) + b

2 = 7 + b

-5 = b

So the slope-intercept form is:

y = 7x - 5

To put this into standard form, move the "x" term to the left side then multiply both sides by -1 since the leading coefficient is negative:

-7x + y = -5

7x - y = 5

Answer 6

y = mx + c

y = 7x - 5