# Use source transformation theory to Find?

Vo and the power

developed by the 300V source, the power developed by the 10A current source and verify that the

total power developed equals the total power dissipated.

### 2 Answers

- PhilomelLv 72 months ago
Circuit Simulator Applet

sources E (v) I(A) P (W)

V 300 34.123 10237

I 125.118 10 1251

tot 11488

res

4 136.493 34.123 4658.

6 163.507 27.251 4456.

40 -125.118 3.128 391.366

10 68. 6.872 472.249

24 164.929 6.872 1133.

8 54.976 6.872 377.799

tot 488.414

- billrussell42Lv 72 months ago
first let me correct the drawing to what I think is your intention, by adding a connection dot.

Then transform the current source and 40Ω resistor to a voltage source as shown.

combine the 4 resistors on the right to 82Ω

then use superposition to get voltage across the 6Ω, call it V1

V1 due to left source:

6 parallel to 82 = 6•82/88 = 5.591 Ω

V1 = 300(5.591/(5.591+4)) = 174.9 V

V1 due to right source:

6 parallel to 4 = 6•4/10 = 2.4 Ω

V1 = 400(2.4/(82+2.4)) = 11.3 V

total is sum, 186.2 V

current thru 6Ω = 186.2/6 = 31.0 amps

current in right loop (CW) is (400–186.2)/82 = 2.61 amps

current in left loop (CW) is (300–186.2)/4 = 28.45 amps

and the two add up to 31 amps

Vo = 2.61•24 = 62.6 volts

power from 300 v source = 300•28.45 = 8535 watts

power from 400 v source: = 400•2.61 = 1044 watts

which is equal to power from 10 A source

you have all the currents, you can use I²R to get the power in each R and add them up.