Factor this number?

X^2y - 2x^2 + 3y - 6

My workbook says the answer is (y - 2)(x^3 + 3) i think its wrong.

7 Answers

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  • 2 months ago
    Favorite Answer

    Since the workbook answer has a x^3 term, and no terms in x or x^2, then the expanded form must also have terms in x^3 and no terms in x or x^2.  So you're right.

    The correct answer is (y-2) ( x^2 + 3)

  • ?
    Lv 7
    2 months ago

    (x^2)y-2x^2+3y-6=

    (x^2)(y-2)+3(y-2)=

    (y-2)(x^2+3)

  • 2 months ago

    x^2y - 2x^2 + 3y - 6

    x^2(y - 2) + 3(y - 2) =

    (x^2 + 3)(y - 2)

    The workbook's answer is correct.

  • 2 months ago

    x²y - 2x² + 3y - 6 => x²y + 3y - 2x² - 6

    so, y(x² + 3) - 2(x² + 3)

    i.e. (y - 2)(x² + 3)

    The workbook is wrong.

    :)>

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  • 2 months ago

    x^2 y - 2 x^2 + 3 y - 6

    = (x^2 + 3) (y - 2)

  • 2 months ago

    x^2y - 2x^2 + 3y - 6

    =x^2(y - 2) + 3(y - 2)

    = (y - 2)(x^2 + 3) Answer//

    The answer in your book is wrong...

  • 2 months ago

    You can't have an x³ factor if the highest x terms are x².

    x²y - 2x² + 3y - 6

    If we factor out an x² from the first 2 terms and a 3 from the last two terms we get:

    x²(y - 2) + 3(y - 2)

    Now we can factor a (y - 2) from that to get:

    (x² + 3)(y - 2)

    That's your factored form.

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