# Factor this number?

X^2y - 2x^2 + 3y - 6

My workbook says the answer is (y - 2)(x^3 + 3) i think its wrong.

### 7 Answers

- MorningfoxLv 72 months agoFavorite Answer
Since the workbook answer has a x^3 term, and no terms in x or x^2, then the expanded form must also have terms in x^3 and no terms in x or x^2. So you're right.

The correct answer is (y-2) ( x^2 + 3)

- Iggy RockoLv 72 months ago
x^2y - 2x^2 + 3y - 6

x^2(y - 2) + 3(y - 2) =

(x^2 + 3)(y - 2)

The workbook's answer is correct.

- Wayne DeguManLv 72 months ago
x²y - 2x² + 3y - 6 => x²y + 3y - 2x² - 6

so, y(x² + 3) - 2(x² + 3)

i.e. (y - 2)(x² + 3)

The workbook is wrong.

:)>

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- Engr. RonaldLv 72 months ago
x^2y - 2x^2 + 3y - 6

=x^2(y - 2) + 3(y - 2)

= (y - 2)(x^2 + 3) Answer//

The answer in your book is wrong...

- llafferLv 72 months ago
You can't have an x³ factor if the highest x terms are x².

x²y - 2x² + 3y - 6

If we factor out an x² from the first 2 terms and a 3 from the last two terms we get:

x²(y - 2) + 3(y - 2)

Now we can factor a (y - 2) from that to get:

(x² + 3)(y - 2)

That's your factored form.