The free-fall acceleration on Mars is 3.7 m/s2. ?
(a) What length pendulum has a period of 1.2-s on Earth?
(b) What length pendulum would have a 1.2-s period on Mars?
- billrussell42Lv 72 months ago
Pendulum period in seconds
T ≈ 2π√(L/g)
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration
(on earth, nominal of 9.8 m/s²)
L ≈ T²g/4π² ≈ 1.2²9.8/4π² = _____ m
L ≈ T²g/4π² ≈ 1.2²3.7/4π² = _____ m