# The free-fall acceleration on Mars is 3.7 m/s2. ?

(a) What length pendulum has a period of 1.2-s on Earth?

(b) What length pendulum would have a 1.2-s period on Mars?

### 1 Answer

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- billrussell42Lv 72 months ago
Pendulum period in seconds

T ≈ 2π√(L/g)

or, rearranging:

g ≈ 4π²L/T²

L ≈ T²g/4π²

L is length of pendulum in meters

g is gravitational acceleration

(on earth, nominal of 9.8 m/s²)

earth

L ≈ T²g/4π² ≈ 1.2²9.8/4π² = _____ m

mars

L ≈ T²g/4π² ≈ 1.2²3.7/4π² = _____ m

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