Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

physics help?

Two children are playing on a balanced seesaw. One child with a mass of 43 kg sits 1.6 m from the center. Where on the other side must the second child sit if her mass is 32 kg?

5 Answers

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  • 2 months ago

    43*1.6=68.8kg m/32=21.5m from center.

  • 2 months ago

    Moments clockwise must equal moments anticlockwise for balacing to occur

    i.e. 43 x 1.6 = 32 x d

    so, d = 68.8/32 => 2.15 metres from centre

    :)>

  • Jim
    Lv 7
    2 months ago

    43*1.6 = 32*d

    d = 43*1.6/32 = 2.1500000 m

    Now you must round answer to 2 sigfigs, never answer with more digits than given!

    2.2 m is correct

  • oubaas
    Lv 7
    2 months ago

    balance implies :

    43*1.6 = 32*d

    d = 1.6*43/32 = 43/20 = 4.3/2 = 2.15 m 

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  • Ash
    Lv 7
    2 months ago

    ∑counterclockwise torque = ∑clockwise torque

    With pivot point at the center of the seesaw

    (43 kg)(1.6 m) = (32 kg)(d)

    d = (43 kg)(1.6 m)/(32 kg)

    d = 2.2 m ← The boy must sit 2.2 m from the centre

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