Anonymous

# physics help?

Two children are playing on a balanced seesaw. One child with a mass of 43 kg sits 1.6 m from the center. Where on the other side must the second child sit if her mass is 32 kg?

### 5 Answers

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- Wayne DeguManLv 72 months ago
Moments clockwise must equal moments anticlockwise for balacing to occur

i.e. 43 x 1.6 = 32 x d

so, d = 68.8/32 => 2.15 metres from centre

:)>

- JimLv 72 months ago
43*1.6 = 32*d

d = 43*1.6/32 = 2.1500000 m

Now you must round answer to 2 sigfigs, never answer with more digits than given!

2.2 m is correct

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- AshLv 72 months ago
∑counterclockwise torque = ∑clockwise torque

With pivot point at the center of the seesaw

(43 kg)(1.6 m) = (32 kg)(d)

d = (43 kg)(1.6 m)/(32 kg)

d = 2.2 m ← The boy must sit 2.2 m from the centre

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