90 asked in Science & MathematicsPhysics · 1 month ago

The angular position of a swinging door is described by 𝜃 = 5.01 + 9.7t + 1.97t2 rad. Determine the angular position, angular speed, and ?

The angular position of a swinging door is described by 𝜃 = 5.01 + 9.7t + 1.97t^2 rad. Determine the angular position, angular speed, and angular acceleration of the door at

(a) t = 0

 ____ rad

 ____ rad/s

 ____ rad/s2

(b) t = 3.10 s

 ____ rad

 ____ rad/s

 ____ rad/s2

answers and process please

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  • 1 month ago
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    (a) t = 0:

    theta = 5.01 rad,

    angular speed = (9.7 + 3.94 t) rad/s = 9.7 rad/s,

    angular acceleration = 3.94 rad/s^2.

    (b)  t = 3.10 s:

    theta = (5.01 + 9.7*3.10 + 1.97*3.10^2) rad/s = use calculator!

    angular speed = (9.7 + 3.94*3.10) rad/s = use calculator;

    angular acceleration = 3.94 rad/s^2.

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