What amount in moles of fluorine yields 2.35 mol of xenon tetrafluoride? Xe + F2 → XeF4?
- Roger the MoleLv 71 month ago
Xe + 2 F2 → XeF4
(2.35 mol XeF4) x (2 mol F2 / 1 mol XeF4) = 4.70 mol F2
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