What amount in moles of phosphorus produces 6.45 mol of tetraphosphorus hexoxide? P4 + O2 → P4O6?
- Roger the MoleLv 72 months ago
P4 + 3 O2 → P4O6
(6.45 mol P4O6) x (1 mol P4 / 1 mol P4O6) = 6.45 mol P4
- ChemTeamLv 72 months ago
The first step is to get a balanced equation:
P4 + 3O2 → P4O6
Next, use the coefficients in the balanced equation to construct a molar ratio between P4 and P4O6:
P4 is to P4O6 ---> 1 : 1 molar ratio
Finally, we write ratio and proportion:
1 is to 1 as x is to 6.45
x = 6.45 moles of P4 required.
Notice that the O2 plays no role, so the act of balancing seems to have played no role. That should not matter. ALWAYS balance the equation first.