Anonymous asked in Science & MathematicsPhysics · 1 month ago

don't understand?

 A baseball player throws a baseball with the same initial velocity 5 different times. Each time the ball is thrown at a different angle. The angles are: 45 degrees, 15 degrees, 60 degrees, 25 degrees, and 80 degrees. (a) List the angles based on the amount of time in the air, from the shortest time to the longest time. (b) List the angles based on the horizontal range the baseball travels from the shortest distance to the longest distance.

4 Answers

  • 1 month ago
    Favorite Answer

    (a)  Steepest throws will spend the longest time in the air.  80, 60, 45, 25, 15.

    (b)  Range is (v^2/2g)*sin(2*theta), so just find out which angles lead to the largest values of  "sin(2*theta)"

    45, 60, 25, 15, 80.

  • oubaas
    Lv 7
    1 month ago

    flying time t = 2tup

    tup = Vo*sin Θ /g = 

    the higher the sin , the higher the time t , the higher the angle (15,  25, 45, 60, 80)

    range R ≡ sin 2Θ

    sin 2*80° = sin 160° = sin 20° = 0.342

    sin 2*15° = sin 30° = 0.5

    sin 2*25° = sin 50° = 0.766

    sin 2*60° = sin 120° = sin 60° = 0.866

    sin 2*45° = sin 90° = 1.00

  • Amy
    Lv 7
    1 month ago

    Correct "velocity" to "speed." Assume no air resistance. Assume flat ground with the ball starting at ground level (I guess the pitcher is in a hole). 

    Time until the ball hits the ground depends only on the vertical motion. Rank the five throws by which has the largest vertical component.

    Horizontal range depends on the horizontal component of velocity and on time in the air, and therefore on the vertical component. You can easily look up the formula or calculate the range individually for each throw.

  • 1 month ago

    calculate range and time for each angle, then sort them as requested. What don't you understand?

    range of object projected at an angle θR = (V²/g)sin(2θ)  V is initial velocity in m/s  g is the acceleration of gravity 9.8 m/s²Time of flight = R/(Vcosθ)

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