A bullet (12g) is fired towards the right from a handgun(0.6kg). The speed of the bullet is 340 m/s, find the recoil velocity of the gun.?
- NCSLv 71 month agoFavorite Answer
Taking right as positive, conserve momentum:
0 = 12g * 340m/s + 600g * V
V = -6.8 m/s → → the sign indicates "to the left." You might not need it in your answer.
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- oubaasLv 71 month ago
Conservation of momentum shall apply :
12*0.34 = V*(0.60+0.012)
recoil velocity V = 12*0.34 / (0.60+0.012) = 20/3 of m/sec