a car speeds over a hill past point a, as shown in the figure. what is the maximum speed the car can have at point a such that its tires will not leave the track of the curvature is 41.8?
- oubaasLv 71 month ago
m*g = m*V^2/r
mass m cancels
V = √ r*g = √ 41.8*9.80 = 20.2 m/sec
V = 20.2*3.6 = 72.9 km/h