Find the concentration of ammonium ions in a solution made by dissolving 3.97g of ammonium phosphate in 500.0 mL of water?

2 Answers

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  • 1 month ago

    Supposing complete ionization:

    (NH4)3PO4 → 3 NH4{+} + PO4{3-}

    (3.97 g (NH4)3PO4) / (149.0867 g (NH4)3PO4/mol) x

    (3 mol NH4{+} / 1 mol (NH4)3PO4) / (0.5000 L) = 0.15977 = 0.160 mol/L NH4{+}

  • david
    Lv 7
    1 month ago

    Find the molar mass of ammoium phosphate.  =  A

      [3.97 / A] / 0.5000  X 3  =  [NH4+]  

      unless you are studying the conc. of slightly soluble substances... Are you? ==  If so then you need the Ksp for ammonium phosphate and do an equilibrium calculation...

    With no more info, I will quit here.

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