What is the boiling point of a solution made of 200g of benzene to which 10.25g of naphthalene has been added? ?

benzene BP= 80.1C and kb=253C/m

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  • david
    Lv 7
    1 month ago

    napthalene == C10H8 == molar mass = 128g/mole

    200g benzene  =  0.2 kg

    molality  =  moles/kg  =  (10.25/128) / 0.2  =  A  

     = = = = = use a calculator

      kb = 253  <<< looks ridiculously high ..  did you leave out a decimal??

      change in BP  =  molality X Kb  =  A X Kb  =  D  

      / / / check Kb .. then use a calculator

      New BP  =  80.1  +  D  ....  this gives the final answer

     

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