What is the boiling point of a solution made of 200g of benzene to which 10.25g of naphthalene has been added? ?
benzene BP= 80.1C and kb=253C/m
- davidLv 71 month ago
napthalene == C10H8 == molar mass = 128g/mole
200g benzene = 0.2 kg
molality = moles/kg = (10.25/128) / 0.2 = A
= = = = = use a calculator
kb = 253 <<< looks ridiculously high .. did you leave out a decimal??
change in BP = molality X Kb = A X Kb = D
/ / / check Kb .. then use a calculator
New BP = 80.1 + D .... this gives the final answer