express y=-3(x+1)^2-5 in standard form?

Answer 1

The expression "standard form" is a bit loaded. This is what I would call standard form for that parabola equation:

y = -3(x + 1)² - 5

-3(x + 1)² - 5 = y

-3(x + 1)² = y + 5

(x + 1)² = -1/3(y + 5) ... standard form

The curve has these parameters:

Vertex: (-1, -5)

Axis: x = -1

Latus rectum: 1/3

Downward concavity

Answer 2

 y = -3(x + 1)^2 - 5 

 y = -3x^2 - 6x - 8

Answer 3

If you mean: y = -3(x+1)^2 -5 then y = -3x^2 -6x -8

Answer 4

y= -3x² -6x -8