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Please help with physics homework: Determine the work done by the applied force? Thanks in advance!?
a) A block of mass 2.20 kg is pushed 2.31 m along a frictionless horizontal table by a constant 17.7N force directed 22.3° below the horizontal. Determine the work done by the applied force (in Joules).
b) Determine the magnitude of the normal force exerted by the table.
c) Determine the magnitude of the force of gravity
d) Determine the magnitude of the net force on the block.
- NCSLv 71 month agoFavorite Answer
a) Work = F*d*cosΘ = 17.7N * 2.31m * cos22.3º = 37.8 J
b) Fn = m*g + F*sinΘ = 2.20kg*9.81m/s² + 17.7N*sin22.3º
Fn = 28.3 N
c) Weight = m*g = 2.20kg * 9.81m/s² = 21.6 N
d) Fnet = F*cosΘ = 17.7N * cos22.3º = 16.4 N horizontal
The net vertical force is zero since the vertical component of the applied force plus the weight is equal to the normal force from the table.
Hope this helps!