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Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

physics maximum force before string breaks?

Two masses m1 = 5.25 kg and m2 = 7.75 kg are connected by a light string, which has a breaking strength of

50.0 N. The masses are moving on a surface with a coefficient of kinetic friction of 0.600. A horizontal

force F is applied to m1 as shown.

Determine the maximum force F that can be applied without breaking the string between masses m1 and

m2.

Help walking me through this would be appreciated :)

Attachment image

2 Answers

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  • NCS
    Lv 7
    1 month ago
    Favorite Answer

    First, apply Newton's Second to m₂:

    m₂*a = T - µ*m₂*g → where T is the maximum tension

    and µ*m₂*g is the friction force.

    7.75 kg * a = 50.0N - 0.600 * 7.75kg * 9.81m/s²

    solves to a = 0.5656

    so that's the maximum allowable system acceleration.

    Now apply N2 to m₁:

    m₁*a = F - T - µ*m₁*g

    5.25kg * 0.5656m/s² = F - 50.0N - 0.600 * 5.25kg * 9.81m/s²

    solves to max F = 83.9 N

    Hope this helps!

  • oubaas
    Lv 7
    1 month ago

    50/m2 = F/(m1+m2)

    F = 50*13/7.75 = 84 N ....in just 1 line 😉

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