Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
physics maximum force before string breaks?
Two masses m1 = 5.25 kg and m2 = 7.75 kg are connected by a light string, which has a breaking strength of
50.0 N. The masses are moving on a surface with a coefficient of kinetic friction of 0.600. A horizontal
force F is applied to m1 as shown.
Determine the maximum force F that can be applied without breaking the string between masses m1 and
Help walking me through this would be appreciated :)
- NCSLv 71 month agoFavorite Answer
First, apply Newton's Second to m₂:
m₂*a = T - µ*m₂*g → where T is the maximum tension
and µ*m₂*g is the friction force.
7.75 kg * a = 50.0N - 0.600 * 7.75kg * 9.81m/s²
solves to a = 0.5656
so that's the maximum allowable system acceleration.
Now apply N2 to m₁:
m₁*a = F - T - µ*m₁*g
5.25kg * 0.5656m/s² = F - 50.0N - 0.600 * 5.25kg * 9.81m/s²
solves to max F = 83.9 N
Hope this helps!
- oubaasLv 71 month ago
50/m2 = F/(m1+m2)
F = 50*13/7.75 = 84 N ....in just 1 line 😉