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Can anybody solve this Age math problem?
Bob is twice the age of Joe who is twice the age of Tim. In 9 years Tim will be the
same age as Bob is now. How old are Bob, Joe and Tim?
- la consoleLv 72 months ago
b: age of Bob now
j: age of Joe now
t: age of Tim now
Bob is twice the age of Joe: → b = 2j
(…) who is twice the age of Tim: → j = 2t
In 9 years Tim will be (t + 9) the same age as Bob is now (b).
t + 9 = b → recall: b = 2j
t + 9 = 2j → recall: j = 2t
t + 9 = 4t
3t = 9
→ t = 3
Recall: j = 2t
→ j = 6
Recall: b = 2j
→ b = 12
- Wayne DeguManLv 72 months ago
We could let the ages of Bob, Joe and Tim be:
4x, 2x and x => ages now
In 9 years we have: 4x + 9, 2x + 9 and x + 9
Hence, x + 9 = 4x
so, 3x = 9
i.e. x = 3
Therefore, ages now are 12, 6 and 3
- Anonymous2 months ago
Bob = 2Joe = 2(2Tim)
Tim + 9 = Bob = 4Tim
3Tim = 9
Tim = 3 Joe = 6 Bob = 12