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# Can anybody solve this Age math problem?

Bob is twice the age of Joe who is twice the age of Tim. In 9 years Tim will be the

same age as Bob is now. How old are Bob, Joe and Tim?

### 3 Answers

Relevance
• b: age of Bob now

j: age of Joe now

t: age of Tim now

Bob is twice the age of Joe: → b = 2j

(…) who is twice the age of Tim: → j = 2t

In 9 years Tim will be (t + 9) the same age as Bob is now (b).

t + 9 = b → recall: b = 2j

t + 9 = 2j → recall: j = 2t

t + 9 = 4t

3t = 9

→ t = 3

Recall: j = 2t

→ j = 6

Recall: b = 2j

→ b = 12

• We could let the ages of Bob, Joe and Tim be:

4x, 2x and x => ages now

In 9 years we have: 4x + 9, 2x + 9 and x + 9

Hence, x + 9 = 4x

so, 3x = 9

i.e. x = 3

Therefore, ages now are 12, 6 and 3

:)>

• Anonymous
2 months ago

Bob = 2Joe = 2(2Tim)

Tim + 9 = Bob = 4Tim

3Tim = 9

Tim = 3 Joe = 6 Bob = 12

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