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Ava asked in Science & MathematicsBiology · 2 months ago

The recessive genes for hemophilia B and Menkes syndrome are 12 map units apart on the X chromosome. ?

The recessive genes for hemophilia B and Menkes syndrome are 12 map

units apart on the X chromosome. The hemophiliac man and the di-heterozygous woman

bearing the trans arrangement of genes in her genotype wonder, what is a chance for

them to have a daughter without any disorder. What is your answer?

1 Answer

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  • 2 months ago

    So, the female's chromosomes could be symbolized as:

    ....Hb-.......MS.... and

    ....Hb+.......ms.... 

    Where Hb- = hemophilia allele and Hb+ = normal allele

    and MS = normal allele and ms = recessive Menkes syndrome allele

    The males only X would be:

    .....Hb-.......MS...

    So, for the daughter to have neither disorder, she would have to get the Hb+ allele from her mother and anything at the MS locus since she will get her father's dominant MS allele.

    Gametes from the female:44% ....Hb-.......MS...44% ....Hb+.......ms.... 6% ....Hb-.......ms.... 6% ....Hb+.......MS.... 

    These last two gametes result from a recombination event between the two loci.

    So, there is a 50% chance of the daughter having neither disorder.

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