Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

? asked in Science & MathematicsChemistry · 2 months ago

What is the new boiling point of a solution containing 25.0 g C6H10O5 in 250.0 mL of water?

(1 mol C6H10O5 = 162.14 g, Kb for water = 0.512°C/m)

1 Answer

Relevance
  • 2 months ago
    Favorite Answer

    C6H10O5 mass = 25.0 g

    1 mol C6H10O5 = 162.14 g,

    moles of C6H10O5 = 25/162.14 = 0.1542 mol

    Volume of H2O = 250 ml

    mass of H2O = 250 ml x 1g = 250g = 0.250Kg

    molality = moles solute/mass solvent kg

    molality = 0.154mol/.250 kg = 0.6168 m

    Kb = 0.512°C/m

    delta Tb = Kb x m = 0.512 x 0.6168 = 0.316 C

    New boiling point = 100 C + 0.316C = 100.316 C

    I hope this helps you!

Still have questions? Get your answers by asking now.