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Can anyone please help me solve this math problem?
A triangle has three vertices given by the points (1,p), (3,0) and (11,0) where p is a positive constant. The triangle is transformed using the matrix [ 6 −2 ]. Given that the transformed 1 2 triangle has an area of 364 square units, what is the value of p?
- jacob sLv 72 months agoFavorite Answer
vertices of triangle
(1,p), (3,0) and (11,0)
1 3 3 11 11 1
area = (1/2) l l + l l + l l
p 0 0 0 0 p
= (1/2)[-3p + 0 +11P]
Given: Area of triangle is 364 sq units
Now, 364 = 4p
p = 91
I hope this helps!