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Anonymous
Anonymous asked in Consumer ElectronicsOther - Electronics · 2 months ago

3-way speaker impedance confusion  ?

I have some drivers gathering dust so i want to make a 3 way speaker, the tweeter is 6 ohm, mid range is 4 ohm and woofer is 8 ohms. I used a calculator to generate a crossover (i will do the math on my own once i have a grasp), but the calculator doesn't show the total ohms? my amp works at either 4 or 8 ohms. How can i work out the total ohms? also what would happen if i bridge the amp with this 3-way speaker?, Here is the generated crossover

4th Order Normal Polarity

2000 Hertz / 250 Hertz

6 Ohm Tweeter / 4 Ohm Mid / 8 Ohm Woofer

2.84 db Bandpass Gain, Spread = 8 : 3 octaves

 Parts List

Capacitors

C1 = 7.08 uF

C2 = 14.04 uF

C3 = 133.43 uF

C4 = 188.51 uF

C5 = 28.25 uF

C6 = 6.29 uF

C7 = 125.75 uF

C8 = 28.45 uF

Inductors

L1 = 0.3 mH

L2 = 1.34 mH

L3 = 1.26 mH

L4 = 7.2 mH

L5 = 0.59 mH

L6 = 0.28 mH

L7 = 9.55 mH

L8 = 4.81 mH

Some reading links would be much appreciated. 

3 Answers

Relevance
  • 1 month ago

    Most manufactured speakers contain drivers 

    that all have the same nominal impedance. 

    When their impedances are unequal, calculations --- 

    and crossover design --- become monumentally difficult.    

                      

    Full laboratory measurement is the best method,   

    as it will give an impedance curve rather than just a fixed-frequency value.    

    A really (really really) well-equipped repair shop may be able to do that for you. 

                          

    Otherwise, use an amplifier that is well known for handling low-impedance 

    loads with ease so you don't have to be concerned about it.   

                      

  • khalil
    Lv 7
    1 month ago

    either 4 or 8 ohms is not acceptable ... which one?

    you may desin filters with different input output impedances.

    study about chebyshev (0.1db) filters design

    https://web.njit.edu/~gilhc/EE494/tutorial.htm

  • Tony B
    Lv 4
    2 months ago

    I can't answer this  but I'd suggest you re-post in “Consumer Electronics”, I guess someone there can help.

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