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Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Half-life calculation question?

Carbon-14, a radioactive isotope, has a half-life of roughly 1,065 years. If a sample starts with 0.16 M C14, how much will be present after 8,996 years?

1 Answer

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  • Ash
    Lv 7
    1 month ago
    Favorite Answer

    Half life formula can be written as

    N = N₀ (½)^(t/t½)

    Given t½ = 1065 years

    N₀ = 0.16 M

    t = 8996 years

    N = ?

    N = 0.16 (½)^(8996/1065)

    N = 0.046 M  ← sample present after 8996 years

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