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Half-life calculation question?
Carbon-14, a radioactive isotope, has a half-life of roughly 1,065 years. If a sample starts with 0.16 M C14, how much will be present after 8,996 years?
- AshLv 71 month agoFavorite Answer
Half life formula can be written as
N = N₀ (½)^(t/t½)
Given t½ = 1065 years
N₀ = 0.16 M
t = 8996 years
N = ?
N = 0.16 (½)^(8996/1065)
N = 0.046 M ← sample present after 8996 years