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# Half-life calculation question?

Carbon-14, a radioactive isotope, has a half-life of roughly 1,065 years. If a sample starts with 0.16 M C14, how much will be present after 8,996 years?

### 1 Answer

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- AshLv 71 month agoFavorite Answer
Half life formula can be written as

N = N₀ (½)^(t/t½)

Given t½ = 1065 years

N₀ = 0.16 M

t = 8996 years

N = ?

N = 0.16 (½)^(8996/1065)

N = 0.046 M ← sample present after 8996 years

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