Yahoo Answers: Answers and Comments for Optimization Problem Differential Calculus? [Mathematics]
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From Evic Panosian
enCA
Mon, 16 Jul 2012 12:20:38 +0000
3
Yahoo Answers: Answers and Comments for Optimization Problem Differential Calculus? [Mathematics]
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From Anonymous: e23r32rf
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Sun, 21 Feb 2016 04:08:56 +0000
e23r32rf

From cryptogramcorner: The 4, 6, and 3 account for the cost per squar...
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Mon, 16 Jul 2012 12:41:17 +0000
The 4, 6, and 3 account for the cost per square foot of the materials.
For example, the area of the floor is width x length, which has been abbreviated wl
so the cost of the material of the floor, at $4 per square foot is 4(wl)
The shed has 4 sides. there are two with area length x height and 2 with areas width x height.
The cost of material is $6 per square foot, so you have
6(lh) and 6(2wh)
( you also seem to have an extra 6(2lh) in what you wrote; there should only be one
6(lh) term.)
The final term 3(wl) accounts for the roof, which costs $4 per square foot.
You also have a fixed volume to account for wlh = 900
Your next step will be to get rid of the w variable, replacing it with (3l/4) in all occurrences.
You volume equation would then be
(3l^2/4)h = 900 This can be solved for h
h = (4/3)900/(l^2) or
h = 1200/(l^2)
You would then use this to get rid of h in your cost equation. At this point
you will have C as a function of only l. You can take derivative, set to 0 and solve for
the optimal value of l. w will be (3/4) of whatever you get for l, and h can be found using
your h = 1200/(l^2) formula.