Yahoo Answers: Answers and Comments for 13 cards dealt. Probability of x aces and y clubs? [Mathematics]
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From Jack
enCA
Mon, 25 Mar 2013 01:07:40 +0000
3
Yahoo Answers: Answers and Comments for 13 cards dealt. Probability of x aces and y clubs? [Mathematics]
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https://ca.answers.yahoo.com/question/index?qid=20130325010739AAwKpxo
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From M3: i will instead break it up into i = nonclub a...
https://ca.answers.yahoo.com/question/index?qid=20130325010739AAwKpxo
https://ca.answers.yahoo.com/question/index?qid=20130325010739AAwKpxo
Mon, 25 Mar 2013 09:21:08 +0000
i will instead break it up into i = nonclub aces, 1 to 3, and j = ace of clubs, 0 to 1, k = nonace clubs, 0 to 12 to get the relation
P(i,j,k) = C(4,i+j)*C(12,k)*C(39,13ijk)/C(52,13)
i = 0 to 3, j = 0 to 1, k = 0 to 12
eg P(2,1,6)
= C(4,3)*C(12,6)*C(39,4)/C(52,13) = .0479%
or P(1,0,4)
= C(4,1)*C(12,4)*C(39,8)/C(52,13) = 19.18%