Yahoo Answers: Answers and Comments for DISCRETE MATHS HELP!! How many Poker (5card) hands consist of a.please EXPLAIN!? [Mathematics]
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From Hannah
enCA
Tue, 29 Oct 2013 04:47:58 +0000
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Yahoo Answers: Answers and Comments for DISCRETE MATHS HELP!! How many Poker (5card) hands consist of a.please EXPLAIN!? [Mathematics]
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From Elizabeth M: If you want the number of choices of m differe...
https://ca.answers.yahoo.com/question/index?qid=20131029044758AAtS1G4
https://ca.answers.yahoo.com/question/index?qid=20131029044758AAtS1G4
Tue, 29 Oct 2013 12:01:42 +0000
If you want the number of choices of m different cards chosen from
n different cards it is n!/(m!(nm)!), where n!=1x2x3x...xn.
1) For each suit you are choosing 5 from 13,
the number of choices =13!/(5!8!)=1287
There are 4 suits so the required number = 1287X4=5148 hands
2) There are 4 aces and 48 notaces.
You want 3 choices from 4 = 4
with 2 choices from 48 = 48!/(2!46!)=1128
So total =4X1128=4512 hands
with