Yahoo Answers: Answers and Comments for Population Genetics: HardyWeinberg Question? [Biology]
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From Norah
enCA
Tue, 14 Jan 2014 23:06:01 +0000
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Yahoo Answers: Answers and Comments for Population Genetics: HardyWeinberg Question? [Biology]
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https://ca.answers.yahoo.com/question/index?qid=20140114230601AAwvO38
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From Paul Jackson: 1. 47%, r is recessive so only rr has the rr p...
https://ca.answers.yahoo.com/question/index?qid=20140114230601AAwvO38
https://ca.answers.yahoo.com/question/index?qid=20140114230601AAwvO38
Wed, 15 Jan 2014 07:34:06 +0000
1. 47%, r is recessive so only rr has the rr phenotype.
2. The frequency of the r allele is q.
q^2 = 0.47
q = √0.47 = 0.69 (rounded)
3. The frequency of the R allele is p = 1  q = 0.31
4. Rr is the homozygote
2pq = 2( 0.686)(0.314) = 0.43
5. both the dominant hetrozygote and the homozygote have the R phenotype.
p^2 + 2pq = (0.31)^2 + 0.43 = 0.53
Note that
p^2 + 2pq + q^2 = 0.53 + 0.47 = 1
From a biological perspective we describe the situation this formula models as follows. In an isolated population with a gene with a single dominate allele and a recessive allele where neither of phenotypes cause any mating preference or change in reproduction rate, the population will eventually reach the equilibrium state described by the HardyWeinberg equation.
This means that if 100 RR's and 100 rr's land on a big isolated island and all start to mate, and we leave them alone for several generations, when we come back can expect to find that 25% percent of the population will be RR. 50% of the population will be Rr, and the other 25% will be rr.